1. Count the letters:
* There are 7 letters in the word "scarlet".
2. Account for repetitions:
* The letter 'a' appears twice.
3. Calculate the factorial:
* If all letters were unique, there would be 7! (7 factorial) arrangements, which is 7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040.
4. Adjust for repetitions:
* Since 'a' repeats twice, we need to divide the factorial by 2! (2 factorial), which is 2 * 1 = 2.
5. Calculate the final result:
* The number of arrangements is 7! / 2! = 5040 / 2 = 2520.
Therefore, there are 2520 different arrangements of the letters in the word "scarlet".