1. Eliminate ε-productions (productions that produce the empty string):
This grammar doesn't have any ε-productions, so we skip this step.
2. Eliminate unit productions (productions of the form A → B, where A and B are non-terminals):
This grammar doesn't have any unit productions either.
3. Convert all productions with more than two symbols on the right-hand side:
We need to introduce new non-terminals to break down the productions:
* For s → 0s1s:
* Introduce a new non-terminal, say `A`.
* Replace the production with:
* `s → 0A`
* `A → s1s`
* For s → 1sos:
* Introduce a new non-terminal, say `B`.
* Replace the production with:
* `s → 1B`
* `B → so`
* For s → 01100011:
* Introduce new non-terminals `C`, `D`, `E`, `F`, `G`.
* Replace the production with:
* `s → 0C`
* `C → 1D`
* `D → 1E`
* `E → 0F`
* `F → 0G`
* `G → 011`
4. Convert all productions with a single terminal on the right-hand side:
We need to introduce more non-terminals:
* For G → 011:
* Introduce new non-terminals `H` and `I`.
* Replace the production with:
* `G → 0H`
* `H → 1I`
* `I → 1`
Resulting Grammar in CNF:
```
s → 0A | 1B
A → s1s
B → so
C → 1D
D → 1E
E → 0F
F → 0G
G → 0H
H → 1I
I → 1
```
Explanation:
* CNF Rules: A grammar is in CNF if all its productions are of the form:
* A → BC (where A, B, and C are non-terminals)
* A → a (where A is a non-terminal and a is a terminal)
* New Non-Terminals: We introduced new non-terminals to break down the original productions into CNF form.
* Final Form: The resulting grammar now only uses productions with two non-terminals or a single terminal on the right-hand side, fulfilling the CNF criteria.